[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"$fzpoIRTSwLM6rwh-7HoAugN5f7nS_7ClwqtchSeLYa_o":3},{"answer":4,"createTime":5,"id":6,"options":7,"origin":8,"question":12,"related":13,"source":19,"type":20},[],"2023-10-20 22:19:24",100905323,[],{"courseId":9,"courseImg":10,"courseName":11},"35eb34968737ab6bd6a007ca75c439dd","https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002F25b30343053994e8940089572d36015b.jpg","移动通信原理","3.18 什么是OFDM信号?为什么它可以有效地抵抗频率选择性衰落",[14,21,26,31,34,39,44,51,56],{"answer":15,"createTime":5,"id":16,"options":17,"question":18,"source":19,"type":20},[],100905316,[],"3.1 信源编码的目的是什么","v1",4,{"answer":22,"createTime":5,"id":23,"options":24,"question":25,"source":19,"type":20},[],100905318,[],"3.3在移动通信中对调制有哪些考虑",{"answer":27,"createTime":5,"id":28,"options":29,"question":30,"source":19,"type":20},[],100905321,[],"3.4什么是相位不连续的FSK ?相位连续的FSK( CPFSK)应当满足什么条件?为什么移动通信中,在使用移频键控一般总是考虑使用CPFSK",{"answer":32,"createTime":5,"id":6,"options":33,"question":12,"source":19,"type":20},[],[],{"answer":35,"createTime":5,"id":36,"options":37,"question":38,"source":19,"type":20},[],100905325,[],"3.19 OFDM系统是如何用IFFT数字信号处理技术实现的",{"answer":40,"createTime":5,"id":41,"options":42,"question":43,"source":19,"type":20},[],100905327,[],"3.20 OFDM有什么优点和缺点",{"answer":45,"createTime":46,"id":47,"options":48,"question":49,"source":19,"type":50},[],"2023-10-20 22:19:25",100905329,[],"3.5 MSK信号数据速率为100kbit\u002Fs.若载波频率为2MHz,求发送1、0时,信号的两个载波频率",7,{"answer":52,"createTime":46,"id":53,"options":54,"question":55,"source":19,"type":50},[],100905330,[],"3.6 已知发送数据序列{bn}={-1 +1 +1 -1 +1 -1 -1 -1}. ①画出MSK信号的相位路径; ②设fc=1.75Rb,画出MSK信号的波形; ③设附加相位初值\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002Fb120af77f3cb4655e8b2584418c51e78.webp\">,计算各码元对应的\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002F14c80a1b2710e18de67e06032215e0d6.webp\">",{"answer":57,"createTime":46,"id":58,"options":59,"question":60,"source":19,"type":50},[],100905331,[],"3.8 GMSK系统空中接口传输速率为 270.83333kbit\u002Fs,求发送信号的两个频率差.若载波频率是f= 900MHz,这两个频率又等于多少"]