[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"$ff-R2ufOh5TQiLn7x41biEnb7fabchwDGmker6YsxzXs":3},{"answer":4,"createTime":5,"id":6,"options":7,"origin":12,"question":16,"related":17,"source":27,"type":28},[],"2023-11-08 19:41:08",104383016,[8,9,10,11],"系统在\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002F9152788e8f501717bc63b305656844ac.png\">作用下的全响应","系统时域特性的表征量","单位阶跃响应与\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002F34988fc9965886cbb4e86eafec41d466.png\">的卷积积分","系统单位阶跃响应的导数",{"courseId":13,"courseImg":14,"courseName":15},"0e2d6525985b6a584a58f7d0df5f3476","https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002Fc4da57c44b27bf86aa70615564695aed.png","信号与系统","‌关于连续时间系统的单位冲激响应h(t),下列说法中错误的是( ).‏",[18,29,37,46,55,63,71,74,83,92],{"answer":19,"createTime":5,"id":20,"options":21,"question":26,"source":27,"type":28},[],104383002,[22,23,24,25],"-2","0.8","-1.8","-1.2","e(t)为激励,r(t)为响应,LTI系统的微分方程为r''(t)+7r'(t)+10r(t)=e''(t)+6e'(t)+4e(t),初值条件为r(0-)=0.8,r'(0-)=0,f(t)=-2u(t),则初始状态r(0+)=( )","v1",0,{"answer":30,"createTime":5,"id":31,"options":32,"question":36,"source":27,"type":28},[],104383005,[33,25,34,35],"1.2","2","0","e(t)为激励,r(t)为响应,LTI系统的微分方程为r''(t)+7r'(t)+10r(t)=e''(t)+6e'(t)+4e(t),初值条件为r(0-)=0.8,r'(0-)=0,f(t)=-2u(t),则初始状态r'(0+)=( )",{"answer":38,"createTime":5,"id":39,"options":40,"question":45,"source":27,"type":28},[],104383007,[41,42,43,44],"(\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002F8ad4c6aab908fa415eee9dd701cba153.png\">)u(t)","(t\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002F3605cf97e7349a0078e3f31d6a7daad8.png\">)u(t)","δ(t)+(\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002F8ad4c6aab908fa415eee9dd701cba153.png\">)u(t)","(t-\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002Fba288ab5bff399000e00f9fb6a96de5a.png\">)u(t)","某连续时间LTI系统的冲激响应h(t)=(1-e-3t)u(t),,若激励信号x(t)=u(t),则该系统的零状态响应是 ( )",{"answer":47,"createTime":5,"id":48,"options":49,"question":54,"source":27,"type":28},[],104383009,[50,51,52,53],"[3e-t+sin(t)]u(t)","3e-tu(t)","[e-t+3sin(t)]u(t)","[3e-t+3sin(t)]u(t)","‏‏已知一线性时不变系统,在相同初始条件下:‏当激励为e(t)时,其全响应为r1(t)=[e-t+2sin(t)]u(t);‏当激励为2e(t)时,其全响应为r2(t)=[2e-t+sin(t)]u(t).‏如果初始条件不变,当激励为3e(t)时,系统的全响应r3(t)为( )‎",{"answer":56,"createTime":5,"id":57,"options":58,"question":62,"source":27,"type":28},[],104383011,[59,60,35,61],"e -t+2e -2t","-e -t-2e -2t","e -t+e -2t","某线性时不变因果系统,已知当激励f 1(t)=u(t)时,t>0的全响应为y 1(t)=3e -t+e -2t;若初始条件不变,当激励f 2(t)=2u(t)时,t>0的全响应为y 2(t)=5e -t,则当激励为零时t>0的全响应为( )‍ (单选题)",{"answer":64,"createTime":5,"id":65,"options":66,"question":70,"source":27,"type":28},[],104383014,[67,35,68,69],"-e-t-2e-2t","e-t+2e-2t","e-t+e-2t","‎某线性时不变因果系统,已知当激励f1(t)=u(t)时,t>0的全响应是y1(t)=3e-t+e-2t,当激励f2(t)=2u(t)时,t>0的全响应是y2(t)=5e-t,则当激励为零时t>0的全响应是( ).(单选题)",{"answer":72,"createTime":5,"id":6,"options":73,"question":16,"source":27,"type":28},[],[8,9,10,11],{"answer":75,"createTime":5,"id":76,"options":77,"question":82,"source":27,"type":28},[],104383019,[78,79,80,81],"-e-atu(t)","ae-atu(t)","(1-e-at)\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002Ff80e5e84449bf8668b6bc7d0203a146c.png\">(t)","-ae-atu(t)","‌单位阶跃信号作用于某线性时不变系统时,零状态响应yzs(t)=(1-e-at)u(t),则此系统单位冲激响应为 ( ) . ‍",{"answer":84,"createTime":5,"id":85,"options":86,"question":91,"source":27,"type":28},[],104383022,[87,88,89,90],"Ae-2tu(t)+Bδ(t),t>0","Ke-2tu(t)","Ke-2t ,t>0","Ke-2tu(t)+Bδ(t)","若描述某二阶连续时间LTI系统的微分方程为y'(t)+2y(t)=2x'(t)+x(t),t>0.则该系统单冲激响应和h(t)的形式为( )",{"answer":93,"createTime":5,"id":94,"options":95,"question":100,"source":27,"type":28},[],104383025,[96,97,98,99],"零状态响应","零输⼊响应","全响应","以上都不对","系统对单位冲激信号δ(t)产生的( )被称为冲激响应,记为h(t). (单选题)"]