[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"$fyVv3UQsyw_yG9yRK1fuqWPhDWaDxtDhkQQMAjKqTfGE":3},{"answer":4,"createTime":5,"id":6,"options":7,"origin":13,"question":20,"related":21,"source":31,"type":32},[],"2024-05-30 20:51:26",136391657,[8,9,10,11,12],"\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002Fa32463a0680b5eb073831ea1eda5f599.png\">","\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002F43bead5c585ee462d0c08cc24b9dc5ce.png\">","\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002F98cb1d9ee90d4f296f852e65d803d124.png\">","\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002Fd525044fc0f3b81bf9ae413189818b1d.png\">","\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002Fc6edd8b8cd67f6223e6b2eaa35344e9e.png\">",{"count":14,"courseId":15,"courseImg":16,"courseName":17,"workId":18,"workName":19},62,"ab85973f2567b92d73a448f09d267b12","https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002F35f97c8324f322a7ca42de7bc5dc5abb.png","离散结构","work_33701403","集合与函数","对于所有的集合 S 和 T,下面哪个集合恒等式是正确的",[22,33,43,53,56,65,74,84,93,103],{"answer":23,"createTime":5,"id":24,"options":25,"question":30,"source":31,"type":32},[],136391654,[26,27,28,29],"f 是映上的,不一定是一对一的","f 是一对一的,不一定是映上的","f 不一定是一对一的,也不一定是映上的","f 必须同时是一对一的和映上的","设 f:R→R 对所有实数 x、y 都具有性质"如果 x<y,那么 f(x)<f(y)"(具有这种性质的函数称为严格增长函数).下面哪个说法是正确的","v1",0,{"answer":34,"createTime":35,"id":36,"options":37,"question":42,"source":31,"type":32},[],"2024-05-31 00:01:13",136391655,[38,39,40,41],"f 不是一个函数,因为 f(3)=9,f(8)=9","f 是一个函数","f 不是一个函数,因为 f(6) 等于 36 也可以等于7","f 不是一个函数,因为没有一个自然数 n 可以使 f(n)=2","设 f:N→N,\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002F5e71d67fd7c1ecb14ea51f5ea9482d71.webp\"> \u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002Ffe5f28262bce57967a31114960256e10.webp\">,以下哪个说法是正确的",{"answer":44,"createTime":45,"id":46,"options":47,"question":52,"source":31,"type":32},[],"2024-05-31 00:05:55",136391656,[48,49,50,51],"其它选项都不是","-1","0","1","设有函数 f:R→R,\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002Fb0be438c9d2b1ff71e84ecb4941c2fd9.webp\">,以及函数 g:R→R,\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002Ff7c89aada2d463b95d612a9e27b06a20.webp\">,那么(f o g)(5)=? 说明:f o g 表示函数 f 与 函数 g 的合成,即复合函数 f( g(x) ),不是函数 g 与函数 f 的合成,这是国内的主流记号方法,与教材正好相反",{"answer":54,"createTime":5,"id":6,"options":55,"question":20,"source":31,"type":32},[],[8,9,10,11,12],{"answer":57,"createTime":35,"id":58,"options":59,"question":64,"source":31,"type":32},[],136391658,[60,61,62,63],"f 是一对一的,不是映上的","f 是一对一的,且是映上的","f 不是一对一的,是映上的","f 既不是一对一的,也不是映上的","设整数有序对集合 \u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002F4324099dc33d80be690e12f2f3ee20ad.webp\">,对于 A->A 上的函数 f( x,y )=( y-1,x+1),下面哪个说法是正确的",{"answer":66,"createTime":35,"id":67,"options":68,"question":73,"source":31,"type":32},[],136391659,[69,70,71,72],"{ 0, 1, 4, 9 }","{ -3, -2, -1, 0, 1, 2 }","{ -9, -4, -1,0, 1, 4 }","{ 0, 1, 4 }","有 f:A →B,其中 A={ -3,-2,-1,0,1,2 } 且 f(x)=x²,那么 B 是下面哪一个集合时,f 是映上的函数",{"answer":75,"createTime":35,"id":76,"options":77,"question":83,"source":31,"type":32},[],136391660,[78,79,80,81,82],"S∪T=S∩T","T-S≠∅","T⊆S∩T","T-S⊆S-T","\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002F36bf778abef9a3abeb37cf0d1a3d39dd.png\">","如果 S⊆T 成立,那么",{"answer":85,"createTime":35,"id":86,"options":87,"question":92,"source":31,"type":32},[],136391661,[88,89,90,91],"f(n)=n²+2n-15","f(n)=n-2, 若 n 是偶数; n-3, 若 n 是奇数","f(n)=n³-5n²+6n","f(n)=n²-3n+2","下列哪一个选项是 f:N→Z 的一对一函数(单射)",{"answer":94,"createTime":5,"id":95,"options":96,"question":102,"source":31,"type":32},[],136391662,[97,98,99,100,101],"偶数集","奇数集","实数集","整数集 { ..., -2, -1, 0, 1, 2, 3, ... }","自然数集 { 0, 1, 2, 3, ... }","设有 f:Z→R,f(n)=2n-3.下面哪一个集合是函数 f 的值域",{"answer":104,"createTime":105,"id":106,"options":107,"question":112,"source":31,"type":32},[],"2024-05-28 18:20:42",136391663,[108,109,110,111],"这不是一个陪域为 R 的函数,因为不存在 n∈N 使得 f(n)=0","这不是一个陪域为 R 的函数,因为 f(-2)=-2\u002F1.5 不属于N","这是一个陪域为 R 的函数,因为对于每个 n∈N,f (n) 是一个实数","这不是一个陪域为 R 的函数,因为 f(1)=2\u002F1.5 不属于 N","在定义域为N(自然数 0, 1, 2, 3, ... )的情况下,\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002Fa12eabe0d56f03c59e71da6153556490.webp\">,以下哪个说法是正确的"]