[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"$fLfQcBEX4dO_InHf0fC8Ni441R8A2K-jEC8zWyd0KBAI":3},{"answer":4,"createTime":5,"id":6,"options":7,"origin":12,"question":19,"related":20,"source":29,"type":93},[],"2024-05-19 21:07:23",144678205,[8,9,10,11],"机理","拟合","实验","化简",{"count":13,"courseId":14,"courseImg":15,"courseName":16,"workId":17,"workName":18},39,"32884ecc8078bd664dc5b804879faac5","https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002F320bee5fb96e260ebc3971940bcbdee9.jpg","自动控制原理","work_35111090","Unit 3","建立控制系统的数学模型的方法有 ()方法和()方法",[21,31,40,48,56,64,73,82,90,94],{"answer":22,"createTime":23,"id":24,"options":25,"question":28,"source":29,"type":30},[],"2024-05-18 16:37:09",144418260,[26,27],"静","动","控制所以关注的稳定性、快速性属于对系统 ()态的要求","v1",0,{"answer":32,"createTime":23,"id":33,"options":34,"question":39,"source":29,"type":30},[],144418261,[35,36,37,38],"不确定","线性定常","离散","非线性","传递函数适用于()系统",{"answer":41,"createTime":42,"id":43,"options":44,"question":47,"source":29,"type":30},[],"2024-05-18 16:37:10",144418262,[45,46],"零极点表达式","基本环节乘积表达式","首一多项式形式的传递函数可以分解因式写成(),对应的增益称为根轨迹增益",{"answer":49,"createTime":42,"id":50,"options":51,"question":55,"source":29,"type":30},[],144418263,[52,53,54],"根轨迹增益","动态增益","静态增益","尾一多项式形式的传递函数可以分解因式写成基本环节乘积的形式,对应的增益称为(),表示系统在阶跃输入下输出稳态值变化量与输入阶跃幅度的比值",{"answer":57,"createTime":42,"id":58,"options":59,"question":63,"source":29,"type":30},[],144418264,[60,61,62],"严格真有理分式","真有理分式","多项式","一个实际的即物理上可实现的线性系统,其传递函数必然是 ()",{"answer":65,"createTime":42,"id":66,"options":67,"question":72,"source":29,"type":30},[],144418265,[68,69,70,71],"阶跃","脉冲","斜坡","加速度","系统传递函数反拉普拉斯变换得到系统的()响应",{"answer":74,"createTime":42,"id":75,"options":76,"question":81,"source":29,"type":30},[],144418266,[77,78,79,80],"微分","积分","拉普拉斯变换","拉普拉斯反变换","零初始条件下,线性定常系统的单位阶跃响应是其单位脉冲响应的 ()",{"answer":83,"createTime":42,"id":84,"options":85,"question":89,"source":29,"type":30},[],144418267,[86,86,87,88],"","s+2","s--2","已知系统在零初始条件下的脉冲响应为 exp(-2t) ,则系统的传递函数为()",{"answer":91,"createTime":5,"id":6,"options":92,"question":19,"source":29,"type":93},[],[8,9,10,11],1,{"answer":95,"createTime":5,"id":96,"options":97,"question":102,"source":29,"type":93},[],144678206,[98,99,100,101],"形式","精度","复杂度","种类","在系统的建模过程中,模型的()和()之间存在矛盾,所以需要应根据系统的实际结构参数及要求的计算精度,略去一些次要因素,使模型既能反映系统的动态本质,又能简化分析计算的工作"]