[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"$fFeaeVtM_z-u9-5cQCrY1S6Yw_oA5R-xY_tLwGT0lW3g":3},{"answer":4,"createTime":5,"id":6,"options":7,"origin":12,"question":16,"related":17,"source":27,"type":28},[],"2026-03-08 12:07:07",321257435,[8,9,10,11],"-π\u002F2","π\u002F2","0","π",{"courseId":13,"courseImg":14,"courseName":15},"9563a4ef30bbb6d6d883d3c683a47f62","https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002F13704a62069169bdc60dd2f922bf2526.jpg","工程数学","设z_1=6-7i,z_2=-6+2i,,则z_1+z_2的幅角为",[18,29,38,47,56,64,67,76,85,94],{"answer":19,"createTime":5,"id":20,"options":21,"question":26,"source":27,"type":28},[],321257430,[22,23,24,25],"δ(ω)","πδ(ω)","2πδ(ω)","1\u002Fjω+πδ(ω)","常数1的傅氏变换为","v1",0,{"answer":30,"createTime":5,"id":31,"options":32,"question":37,"source":27,"type":28},[],321257431,[33,34,35,36],"二级零点","三级零点","二级极点","三级极点","z=-1是函数f(z)=((z+1)^3)\u002F(z(z^2+1)^3 ) 的",{"answer":39,"createTime":5,"id":40,"options":41,"question":46,"source":27,"type":28},[],321257432,[42,43,44,45],"1\u002Fs","2πi","┬(n→∞) α_n=0","jπ(δ(ω+k)-δ(ω-k))",""1"的拉氏变换为",{"answer":48,"createTime":5,"id":49,"options":50,"question":55,"source":27,"type":28},[],321257433,[51,52,53,54],"┬(z→z_0 ) f(z)=f(z_0)","┬(z→z_0 ) [f(z)-f(z_0)]=0","┬(Δz→0) f(z_0+Δz)=f(z_0)","┬(z→z_0 ) [f(z)-f(z_0)]≠0","若函数f(z)在z_0不连续,则",{"answer":57,"createTime":5,"id":58,"options":59,"question":63,"source":27,"type":28},[],321257434,[60,61,10,62],"c_1","┬(z→z_0 ) (z-z_0)f(z)","┬(z→z_0 ) d\u002Fdz [(z-z_0 )^2 f(z)]","设z_0是f(z)的孤立奇点, z_0是f(z)的二级极点,则Re⁡s [f(z),z_0]=",{"answer":65,"createTime":5,"id":6,"options":66,"question":16,"source":27,"type":28},[],[8,9,10,11],{"answer":68,"createTime":5,"id":69,"options":70,"question":75,"source":27,"type":28},[],321257436,[71,72,73,74],"8\u002Fs","8\u002Fjs","8πδ(s)","1\u002Fjs+8πδ(s)","8的拉氏变换为",{"answer":77,"createTime":5,"id":78,"options":79,"question":84,"source":27,"type":28},[],321257437,[80,81,82,83],"u(x,y),v(x,y)在z_0点可微","在z_0点∂u\u002F∂x=∂v\u002F∂y,∂u\u002F∂y=-∂v\u002F∂x","在z_0点u(x,y),v(x,y)可微且∂u\u002F∂x=∂v\u002F∂y,∂u\u002F∂y=-∂v\u002F∂x","f(z)在z_0点可导","函数f(z)=u(x,y)+iv(x,y)在z_0点解析的充要条件是",{"answer":86,"createTime":5,"id":87,"options":88,"question":93,"source":27,"type":28},[],321257438,[89,90,91,92],"","20πδ(ω)","10πδ(ω)","1\u002Fjω+5πδ(ω)","常数5的傅氏变换为",{"answer":95,"createTime":5,"id":96,"options":97,"question":101,"source":27,"type":28},[],321257439,[98,10,99,100],") (z_0))\u002F4","2πif(z_0)","2πif^((4)) (0)","设f(z)在单连域G内解析,C为G内任意一条正向简单闭曲线, z_0是C内的一点,则积分∮_C▒〖(f(z))\u002F(z-z_0 )^5 dz〗="]