[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"$f-tPFN4ajfj6SjO7WSKF3yzdGwlTPu3IZuq83b1J2d28":3},{"answer":4,"createTime":5,"id":6,"options":7,"origin":8,"question":12,"related":13,"source":17,"type":18},[],"2026-04-24 21:30:21",350245096,[],{"courseId":9,"courseImg":10,"courseName":11},"53e1d2ef4961cca8eea3e23969ad2cb9","https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002F03a579384a6dc297c89809b582fcc767.png","默认课程","题目:d 是一个字典,d = {123:"123", 456:"456", 789:"789"} 请补充如下代码: ①将字典 d 中所有值以列表形式输出 ②将字典 d 中所有键以列表形式输出 d = {123:"123", 456:"456", 789:"789"} print(___①__) print(___②__)",[14,19,24,29,34,39,44,49,54],{"answer":15,"createTime":5,"id":6,"options":16,"question":12,"source":17,"type":18},[],[],"v1",2,{"answer":20,"createTime":5,"id":21,"options":22,"question":23,"source":17,"type":18},[],350245097,[],"题目:完善代码完成如下功能: (1)向字典d中添加键值对"化学":205. (2)删除"英语"对应的键值对. (3)删除"生物"对应的键值对. (4)按顺序打印字典 d 全部信息,格式为:键:值 d = {"数学":101,"语文":202,"英语":203,"物理":204,"生物":206} 【 ? 】= 205 d["数学"]= 201 if "英语" in d.keys(): 【 ? 】("英语") if "生物" in d: del(【 ? 】) for key in d: print("{}:{}".format(key,【 ? 】))",{"answer":25,"createTime":5,"id":26,"options":27,"question":28,"source":17,"type":18},[],350245098,[],"题目:dictMenu中存放了你的双人下午套餐的价格,让Python帮忙计算并输出消费总额. dictMenu = {'卡布奇洛':32,'摩卡':30,'抹茶蛋糕':28,'布朗尼':26} 【1】 for i in 【2】: sum += i print(sum)",{"answer":30,"createTime":5,"id":31,"options":32,"question":33,"source":17,"type":18},[],350245099,[],"题目:有如下值的列表[11,22,33,44,55,66,77,88,99,90],将所有 大于等于66的值保存至字典的第一个key的值中,将小于66的值保 存至第二个key的值中. 即:{'key1':大于等于66的所有值,'key2':小于 66 的所有值} ls= [11,90,88,33,44,66,55,77,22,99] max66=【 1 】 min66=[] for 【 2 】 in ls: if(x>=66): max66.append(x) else: 【 3 】 dic66 =【 4 】 dic66["key1"]=max66 dic66["key2"]=min66 print(dic66)",{"answer":35,"createTime":5,"id":36,"options":37,"question":38,"source":17,"type":18},[],350245100,[],"题目:列表 ls 中存储了我国 39 所 985 高校所对应的学校类型, 请以这个列表为数据变量,完善 Python 代码,统计输出各 类型的数量. 下列程序的输出结果为: 师范:2 民族:1 理工:13 农林:2 综合:20 军事:1 ''' ls = ["综合", "理工", "综合", "综合", "综合", "综合", "综合", "综合", \\ "综合", "综合", "师范", "理工", "综合", "理工", "综合", "综合", \\ "综合", "综合", "综合", "理工", "理工", "理工", "理工", "师范", \\ "综合", "农林", "理工", "综合", "理工", "理工", "理工", "综合", \\ "理工", "综合", "综合", "理工", "农林", "民族", "军事"] d=【 ?】 for word in 【 ?】: d[word] = 【 ?】 + 1 for x in d: print("{}:{}".format(【 ?】))",{"answer":40,"createTime":5,"id":41,"options":42,"question":43,"source":17,"type":18},[],350245101,[],"题目:填空完善程序,计算列表元素之和以及各元素出现的次数 s=[1,2,3,3,3,5,1,2,8,4,5,6,7,8] print("列表和是%d"【 1 】) dt={} for i in s: dt[i]=【2】+1 for 【 3 】 in dt: print(f"{x}出现的次数是:{【4】}")",{"answer":45,"createTime":5,"id":46,"options":47,"question":48,"source":17,"type":18},[],350245102,[],"题目:字符串去重. 任务描述:输入一个非空字符串,去除重复的字符后,从小到大排序输出为一个新字符串. 输入格式:一个非空字符串 输出格式:去重排序后的字符串 输入样例: Life is short, we need Python! 输出样例: !,LPdefhinorstwy x=input() #输入一个字符串x s= 【1】 #把字符串x转换为集合s a=【2】 #把集合s转换为列表a a.sort() #对列表a的元素进行升序排序 print(【3】) #把列表a的元素连接为一个字符串并输出",{"answer":50,"createTime":5,"id":51,"options":52,"question":53,"source":17,"type":18},[],350245103,[],"题目:文本字符分析. 输入一个字符串,按照字符出现频率的降序打印字母. 输入样例: 请输入一个字符串:werwwe 输出样例: w:3 e:2 r:1 【1】= input('请输入一个字符串:') d =【2】 for ch in s: 【3】 = d.get(ch,0)+1 ls = list(【4】) 【5】(key= lambda x : x[1],reverse=True) for i in range(【6】): dkey,dvalue = ls[i] print('{}:{}'.format(dkey,dvalue))",{"answer":55,"createTime":5,"id":56,"options":57,"question":58,"source":17,"type":18},[],350245104,[],"题目:成绩排序. 给出班里某门课程的成绩单,请你按成绩从高到低对成绩单排序输出,如果有相同分数则名字字典序小的在前. 输入:第一行为n (0 < n < 20),表示班里的学生数目; 接下来的n行,每行为每个学生的名字和他的成绩, 中间用单个空格隔开. 名字只包含字母且长度不超过20,成绩为一个不大于100的非负整数. 输出:把成绩单按分数从高到低的顺序进行排序并输出,每行包含名字和分数两项,之间有一个空格. 样例输入: 4 Kitty 80 Hanmeimei 90 Joey 92 Tim 28 样例输出: Joey 92 Hanmeimei 90 Kitty 80 Tim 28 【1】=int(input()) dt={} for i in range(n): key,value=【2】 【3】=eval(value) lt=sorted(【4】,key=lambda x:(-x[1],x[0])) for x in lt: print(x[0],x[1])"]