[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"$f2V9JCbTKi_oqZFQqK3XDx20h1F8NcwhERp3AdnikSZY":3},{"answer":4,"createTime":5,"id":6,"options":7,"origin":12,"question":19,"related":20,"source":30,"type":31},[],"2023-06-16 22:25:25",66084064,[8,9,10,11],"向左移动","向右移动","不发生移动","根据CaO的颗粒大小",{"count":13,"courseId":14,"courseImg":15,"courseName":16,"workId":17,"workName":18},18,"22bc2e2f0b3d45a3948bc47c2c819147","https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002F4f61ca70ff254b5ed741fa7c778a6832.png","物理化学","work_28223637","新建作业20230611113520","在一定温度下达到平衡,现在不改变温度和CO2 的分压力,也不改变CaO(s)颗粒的大小,只降低CaCO3(s)颗粒的直径,增加分散度,则平衡将( ). A、 B、 C、",[21,32,41,50,53,62,71,80,89,98],{"answer":22,"createTime":5,"id":23,"options":24,"question":29,"source":30,"type":31},[],66084061,[25,26,27,28],"49.33 kPa","77.94 kPa","20.72 kPa","32.89 kPa","= 0.21,j(N2)= 0.79,若大气压力为98.66 kPa,那么O2的分压力最接近的数值为:( )","v1",0,{"answer":33,"createTime":5,"id":34,"options":35,"question":40,"source":30,"type":31},[],66084062,[36,37,38,39],"随温度升高,饱和蒸气和饱和液体的摩尔体积皆增大","随温度升高,饱和蒸气和饱和液体的摩尔体积皆减小","随温度升高,饱和蒸气的摩尔体积减小,而饱和液体的摩尔体积增大","随温度升高,饱和蒸气的摩尔体积增大,而饱和液体的摩尔体积减小","8.讨论气体液化的气液平衡时,饱和蒸气和相应的饱和液体的摩尔体积与温度的关系,正确的论述是:( )",{"answer":42,"createTime":5,"id":43,"options":44,"question":49,"source":30,"type":31},[],66084063,[45,46,47,48],"摩尔热力学能","摩尔焓","摩尔吉布斯函数","摩尔熵","在一定温度和压力下a,b任意两相平衡时,两相中下述物理量相等的是( )",{"answer":51,"createTime":5,"id":6,"options":52,"question":19,"source":30,"type":31},[],[8,9,10,11],{"answer":54,"createTime":5,"id":55,"options":56,"question":61,"source":30,"type":31},[],66084065,[57,58,59,60],"控制适当的反应时间","控制适当的反应温度","增加反应物A的浓度","以上操作都可以","在一个连串反应A\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002Fec1760171fefbd0e5bfd53ba46e036e1.png\">https:\u002F\u002Fp.ananas.chaoxing.com\u002Fstar3\u002Forigin\u002Faea2792dec503602e3aab4b41c1fdfeb.png Y \u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002Fec1760171fefbd0e5bfd53ba46e036e1.png\">https:\u002F\u002Fp.ananas.chaoxing.com\u002Fstar3\u002Forigin\u002Faea2792dec503602e3aab4b41c1fdfeb.png Z中,如果我们需要的是中间产物Y,那么为了得到产品的最高产率,我们应当:( )",{"answer":63,"createTime":5,"id":64,"options":65,"question":70,"source":30,"type":31},[],66084066,[66,67,68,69],"反应的标准摩尔焓变","标准平衡常数","反应标准摩尔熵变","反应的速率系(常)数","加入催化剂可使化学反应的下列物理量中哪一个改变:( )",{"answer":72,"createTime":5,"id":73,"options":74,"question":79,"source":30,"type":31},[],66084067,[75,76,77,78],".Cu&reg;Fe&reg;Zn&reg;Ca","Ca&reg;Zn&reg;Fe&reg;Cu","Ca&reg;Fe&reg;Zn&reg;Cu","Ca&reg;Cu&reg;Zn&reg;Fe","=0.337 V.在惰性电极上,金属析出的顺序为:( )",{"answer":81,"createTime":5,"id":82,"options":83,"question":88,"source":30,"type":31},[],66084068,[84,85,86,87],"与A的起始浓度无关","与A的起始浓度成正比","与A的起始浓度成反比","与A的起始浓度平方成反比","二级反应 2A\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002Fdf219a67ecf8b15c494c574882b369aa.png\">https:\u002F\u002Fp.ananas.chaoxing.com\u002Fstar3\u002Forigin\u002Fd1c452cb799c001e28620f311acedbdf.png Y其半衰期:( )",{"answer":90,"createTime":5,"id":91,"options":92,"question":97,"source":30,"type":31},[],66084069,[93,94,95,96],"2.5 dm3","2.0 dm3","3.0 dm3","0.5 dm3","在100 kPa下,当1.0 dm3理想气体从273 K升高到546 K时,其体积将变为:( )",{"answer":99,"createTime":5,"id":100,"options":101,"question":106,"source":30,"type":31},[],66084070,[102,103,104,105],"不能液化","低温高压下才能液化","低温下能液化","高压下能液化","理想气体的液化行为是:( )"]