[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"$fMi99gENrgityn3A_8hgaNMkvRnAG5bLEWmr0AM8RgZE":3},{"answer":4,"createTime":5,"id":6,"options":7,"origin":11,"question":17,"related":18,"source":28,"type":42},[],"2024-10-25 12:26:30",1006309654,[8,9,10,8],"9","8","9*9",{"courseId":12,"courseImg":13,"courseName":14,"workId":15,"workName":16},"1000000860","https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002Fcf3bb414b5ea2367f316b2d3561124c7.jpg","[共享课]人工智能","59859673","搜索算法的介绍和应用","在下图八数码问题中,需要通过移动将杂乱的8个方块按照右侧的顺序进行排列,那么该问题的状态空间的大小是( )?\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002Ffeb172e27c2784719c655359c75c69df.png\">",[19,30,39,43,51],{"answer":20,"createTime":5,"id":21,"options":22,"question":27,"source":28,"type":29},[],1006309652,[23,24,25,26],"深度优先图搜索(BFS)可以保证找到解(如果存在至少一解)","一致代价搜索(UCS)不一定总能找到最优解","存在广度优先树搜索有解而深度优先树搜索无解的案例","存在深度优先树搜索有解而广度优先树搜索无解的案例","对于有限状态图上的搜索问题,以下说法正确的有( )","v2",1,{"answer":31,"createTime":5,"id":32,"options":33,"question":38,"source":28,"type":29},[],1006309653,[34,35,36,37],"不在目标位置的数码总数","各数码到目标位置的曼哈顿距离总和","数码1、2、3、4移动到正确位置的步数","都不正确","在如下图的八数码问题中,如果A格与B格相邻且B为空,则A可以移动至B.以下可以作为八数码问题的一致启发式函数的有( ).\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002F9f7b233164e43f4a605e3be2d392c85e.png\">",{"answer":40,"createTime":5,"id":6,"options":41,"question":17,"source":28,"type":42},[],[8,9,10,8],0,{"answer":44,"createTime":5,"id":45,"options":46,"question":49,"source":28,"type":50},[],1006309655,[47,48],"对","错","对于一个边损耗非负的有限图,采用广度优先树搜索可以得到最优解,并且对每条边加上一个相同的非负损耗c>0之后,最优路径保持不变",3,{"answer":52,"createTime":5,"id":53,"options":54,"question":59,"source":28,"type":42},[],1006309656,[55,56,57,58],"G1","G2","G3","均不可能","在下列图搜索问题中,S为起始节点,G1、G2、G3均为目标节点,则采用一致代价找到的解是( )\u003Cimg src=\"https:\u002F\u002Ftihai-oss-cloud.itihey.com\u002Fimg\u002Ff61ef9bf59f17ce5fe78d71ec4436357.png\">"]