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单选题 若A-B=Ф,则下列哪个结论不可能正确?( )
B. B
A
C. AB
学科：离散数学
时间：2024-11-29 12:59:02
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题目1单选题
集合的以下运算律不成立的是( )A. A⊕B=B⊕AB. A∪B=B∪AC. A-B=B-AD. A∩B=B∩A
题目2单选题
设A={a,{a}},下列命题错误的是( )A. {{a}}<img src="https://tihai-oss-cloud.itihey.com/img/0638b29507bd61d6b1a3e83a7184a8dd.webp">P(A)B. {{a}}<img src="https://tihai-oss-cloud.itihey.com/img/46bf924d40dcd9b8f33d9ea12435a077.webp">P(A)C. {a}<img src="https://tihai-oss-cloud.itihey.com/img/46bf924d40dcd9b8f33d9ea12435a077.webp">P(A)D. {a}<img src="https://tihai-oss-cloud.itihey.com/img/0638b29507bd61d6b1a3e83a7184a8dd.webp">P(A)
题目3单选题
若A ⊆ B且B ⊆ C,则( )A. A ∪ C = BB. A ∩ C = ∅C. A ⊆ CD. A = C
题目4单选题
若集合 E = {x | x 是小于 5 的自然数}, F = {y | y 是奇数且小于 7 }, 那么 E ∩ F 是A. {0, 1, 2, 3, 4}B. {0, 2, 4}C. {1, 3}D. {1, 2, 3, 4}
题目5单选题
若A-B=Ф,则下列哪个结论不可能正确?( )A. A=ФB. B<img src="https://tihai-oss-cloud.itihey.com/img/66396b9ef10dc4b1f8d5a58967bb120a.webp">AC. A<img src="https://tihai-oss-cloud.itihey.com/img/66396b9ef10dc4b1f8d5a58967bb120a.webp">BD. B=Ф
题目6单选题
设集合E ={2,3,4,5,6}为全集,A= {2,5},B ={2,6,5},C ={3,6},则P(B-A)为()A. <img src="https://tihai-oss-cloud.itihey.com/img/b342dfd781650e8b4a11b4cb4743fbec.webp">B. {{6}}C. {<img src="https://tihai-oss-cloud.itihey.com/img/b342dfd781650e8b4a11b4cb4743fbec.webp">}D. {<img src="https://tihai-oss-cloud.itihey.com/img/b342dfd781650e8b4a11b4cb4743fbec.webp">,{6}}
题目7单选题
判断下列命题哪个正确?( )A. 若A为非空集,则A<img src="https://tihai-oss-cloud.itihey.com/img/3fa69b5ed2e15416e4e45b125cfc90d9.webp">A∪A成立B. 若A∪B=A∪C,则B=CC. P(A∩B)<img src="https://tihai-oss-cloud.itihey.com/img/3fa69b5ed2e15416e4e45b125cfc90d9.webp">P(A)∩P(B) (P(S)表示S的幂集)D. {a,b}={b,a}
题目8单选题
在集合运算中,( )对⊕可分配A. ⊕B. -C. <img src="https://tihai-oss-cloud.itihey.com/img/b20005926eaaa9be5814bed1e5b16da3.webp">D. <img src="https://tihai-oss-cloud.itihey.com/img/5a93af0394c634aa1be9de432251b09a.webp">
题目9单选题
判断下列关系哪个正确?( )A. {a,b}∈{a,b,{a},{b}}B. {Ф}<img src="https://tihai-oss-cloud.itihey.com/img/46bf924d40dcd9b8f33d9ea12435a077.webp">{Ф,{{Ф}}}C. {Ф}∈{Ф,{{Ф}}}D. Ф∈{{Ф}}
题目10单选题
若A ∪ B = A,则( )A. A = BB. A ∩ B = ∅C. B ⊆ AD. A ⊆ B
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