题目7单选题
同步 RS 触发器的特性方程(CP=1 时有效)是( )A. Q*=S+<img src="https://tihai-oss-cloud.itihey.com/img/fb029521dc6c1c9f3bae90512aa86d51.png">Q,RS=0B. Q*=<img src="https://tihai-oss-cloud.itihey.com/img/403200411aabf76ca0518c58e4445698.png">+<img src="https://tihai-oss-cloud.itihey.com/img/fb029521dc6c1c9f3bae90512aa86d51.png">Q,<img src="https://tihai-oss-cloud.itihey.com/img/fb029521dc6c1c9f3bae90512aa86d51.png">+<img src="https://tihai-oss-cloud.itihey.com/img/403200411aabf76ca0518c58e4445698.png">=1C. Q*=S+RQ,RS=1D. Q*=<img src="https://tihai-oss-cloud.itihey.com/img/403200411aabf76ca0518c58e4445698.png">+RQ=0