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简答题 定义一个接口,接口中有3个抽象方法如下. (1)"long fact(int m);"方法的功能为求参数的阶乘. (2)"long intPower(int m,int n);"方法的功能为求参数m的n次方. (3)"boolean findFactor(int m,int n);"方法的功能为判断参数m加上参数n的和是否大于100. 定义类实现该接口,编写应用程序,调用接口中的3个方法,并将调用方法所得的结果输出
学科：面向对象程序设计（Java）
时间：2026-05-18 20:06:09
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题目1填空题
读下面程序,写出程序运行结果. class Father { int num1=0; public Father(){ System.out.println("num1:"+num1);} public Father(int num1){ this.num1=num1; System.out.println("num1:"+num1); } } class Son extends Father{ int num2=10; public Son(){System.out.println("num2:"+num2);} public Son(int i,int j){ super(i); num2=j; System.out.println( "num1:"+num1+",num2:"+num2); } } public class Demo{ public static void main(String []args){ Father father=new Father(); Son son=new Son(); Son son1=new Son(20,30); } } 运行结果为题目2填空题
在(1)~(3)处填上适当的语句,使程序能正常运行 class Person { public void show(){} } (1) { public void show(){ System.out.println("Student");} } class Teacher extends Person{ (2) { System.out.println("Teacher");}} public class Demo{ public static void main(String []args){ (3) p.show(); p=new Student(); p.show(); p=new Teacher(); p.show(); }}题目3填空题
读下面程序,写出程序运行结果. class Point{ int x; public Point(){x=0;} public Point(int x){this.x=x;} public void show(){System.out.println(x);}} class SPoint extends Point{ int y; public SPoint(){y=0;} public SPoint(int x,int y){super(x); this.y=y;} public void show(){System.out.println(x+","+y);}} public class tempDemo{ public static void main(String []args){ Point p=new Point(); p.show(); Point p1=new Point(2); p1.show(); SPoint sp=new SPoint(); sp.show(); SPoint sp1=new SPoint(2,3); sp1.show(); }} 运行结果为题目4填空题
读下面程序,写出程序运行结果. class Point{ int x=1; public void show(){System.out.println(x);}} class SPoint extends Point{ int y=2; public void show(){System.out.println(x+","+y);}} class PPoint extends Point{ int z=3; public void show(){System.out.println(x+","+z);}} public class tempDemo{ public static void main(String []args){ Point p; p=new Point(); p.show(); p=new SPoint(); p.show(); p.x=2; p.show(); p=new PPoint(); p.show(); }} 运行结果为题目5填空题
在(1)~(3)处填上适当的语句,使程序能正常运行.. (1) class Employee { public abstract void show(); } class SalEmp extends Employee{ public void show(){System.out.println("SalEmp");} } class TelEmp extends Employee { (2) { System.out.println("TelEmp ");} } public class Demo{ public static void main(String []args){ SalEmp p=new SalEmp(); p.show(); (3) p1=new TelEmp (); p1.show(); }}题目6填空题
读下面程序,写出程序运行结果. class Person{ int a,b; public Person(int a,int b){ System.out.println("a,b:"+a+b); }} class Student extends Person{ int c; public Student(int a,int b,int c){ super(a,b); this.c= c; System.out.println("c:"+c); } public void show(){ System.out.println("a,b,c:"+a+b+c); }} public class classDemo1{ public static void main(String []args){ Person p1=new Person(1,2); Student p2=new Student(2,3,4); p2.show(); }} 运行结果为题目7填空题
读下面程序,写出程序运行结果. abstract class Graph{ int a; public Graph(){a=1;} public Graph(int a){this.a=a; } public abstract void showArea(); } class Rect extends Graph{ int b; public Rect(int a,int b){super(a); this.b= b; } public void showArea(){ System.out.println("Area:"+(a*b));} } class Circle extends Graph{ public Circle(){}; public Circle(int a){super(a);} public void showArea(){ System.out.println("Area:"+(3.14*a*a)); } } public class classDemo1{ public static void main(String []args){ Graph g1; g1=new Rect(2,3); g1.showArea(); g1=new Circle(2); g1.showArea(); g1= new Circle(); g1.showArea(); } } 运行结果为题目8填空题
在(1)~(3)处填上适当的语句,使程序能正常运行.. abstract class Person { public (1) show(); } class Student extends Person{ public (2) { System.out.println("Student");}} (3) { public void show(){ System.out.println("Teacher");}} public class Demo{ public static void main(String []args){ Person p; p=new Student(); p.show(); p=new Teacher(); p.show(); }}题目9简答题
按要求编写一个Java应用程序: (1)定义一个接口CanCry,描述会吼叫的方法public void cry(). (2)分别定义狗类(Dog)和猫类(Cat),实现CanCry接口.实现方法的功能分别为:打印输出"我是狗,我的叫声是汪汪汪"、"我是猫,我的叫声是喵喵喵". (3)定义一个主类G, ①定义一个void makeCry(CanCry c)方法,其中让会吼叫的事物吼叫. ②在main方法中创建狗类对象(dog)、猫类对象(cat)、G类对象(g),用g调用makecry方法,让狗和猫吼叫题目10简答题
定义一个接口,接口中有3个抽象方法如下. (1)"long fact(int m);"方法的功能为求参数的阶乘. (2)"long intPower(int m,int n);"方法的功能为求参数m的n次方. (3)"boolean findFactor(int m,int n);"方法的功能为判断参数m加上参数n的和是否大于100. 定义类实现该接口,编写应用程序,调用接口中的3个方法,并将调用方法所得的结果输出下载 题海APP
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