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单选题 What will be the output of the following Python code? a=[13,56,17] a.append([87]) a.extend([45,67]) print(a)
学科：Python程序设计（双语）
时间：2023-09-27 03:19:44
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题目1单选题
What will be the output of the following Python code? >>> l=["good", "oh!", "excellent!", "#450"] >>> [n for n in l if n.isalpha() or n.isdigit()]A. ['oh!', 'excellent!', '#450']B. ['good', 'oh', 'excellent', '450' ]C. ['good', '#450']D. ['good']
题目2单选题
What will be the output of the following Python code? lst=[3,4,6,1,2] lst[1:2]=[7,8] print(lst) lst[3]=[9,10] print(lst)A. [3, 7, 8, 6, 1, 2] [3, 7, 8, [9, 10], 1, 2]B. [3,[7,8],6,1,2] [3, 7, 8, 9, 10, 1, 2]C. [3,4,6,7,8] [9,10,4,6,7,8]D. Syntax error
题目3单选题
What will be the output of the following Python code? a=[13,56,17] a.append([87]) a.extend([45,67]) print(a)A. [13, 56, 17, [87], 45, 67]B. [13, 56, 17, [87], [45, 67]]C. [13, 56, 17, 87, 45, 67]D. [13, 56, 17, 87,[ 45, 67]]
题目4单选题
What will be the output of the following Python code? >>>list("a#b#c#d".split('#'))A. ['a#b#c#d']B. ['a b c d']C. ['a', 'b', 'c', 'd']D. ['abcd']
题目5单选题
What will be the output of the following Python code? >>> s=["pune", "mumbai", "delhi"] >>> [(w.upper(), len(w)) for w in s]A. [PUNE, 4, MUMBAI, 6, DELHI, 5]B. ['PUNE', 4, 'MUMBAI', 6,'DELHI', 5]C. ErrorD. [('PUNE', 4), ('MUMBAI', 6), ('DELHI', 5)]
题目6单选题
What will be the output of the following Python code? lst=[[1,2],[3,4]] print(sum(lst,[]))A. [1,2,3,4]B. ErrorC. [[3],[7]]D. [10]
题目7单选题
Suppose list1 is [2, 33, 222, 14, 25], What is list1[:-1]A. ErrorB. [25, 14, 222, 33, 2]C. [2, 33, 222, 14]D. 25
题目8单选题
What will be the output of the following Python code? a=[1,2,3] b=a.append(4) print(a) print(b)A. [1,2,3] [1,2,3,4]B. [1, 2, 3, 4] NoneC. Syntax errorD. [1,2,3,4] [1,2,3,4]
题目9单选题
What will be the output of the following Python code? num = ['One', 'Two', 'Three'] for i, x in enumerate(num): print('{}: {}'.format(i, x),end=" ")A. Exception is thrownB. 0: One 1: Two 2: ThreeC. One Two ThreeD. 1: 2: 3
题目10单选题
ls=[[1,2,3],[4,5,6],[7,8,9]], the value of ls[1][1] isA. 1B. 9C. errorD. 5
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